The centers of a 11 kg lead ball and a 70 g lead ball are separated by 8.0 cm. What gravitational force does each exert on the other?
Gravitaional constant, G,
= 6.67*10-11 N (m/kg)²
Force
= GMm/r²
= 6.67*10-11 * 11 * 0.07/0.08²
=8.0*10^(-9) N
To calculate the gravitational force between two objects, we can use Newton's law of universal gravitation formula:
F = (G * m1 * m2) / r^2
Where:
F is the gravitational force
G is the gravitational constant (6.67430 × 10^-11 Nm^2/kg^2)
m1 and m2 are the masses of the two objects
r is the distance between the centers of the objects
In this case, we have:
m1 = 11 kg (mass of the larger lead ball)
m2 = 70 g = 0.07 kg (mass of the smaller lead ball)
r = 8.0 cm = 0.08 m (distance between the centers of the balls)
So, plugging in these values into the formula:
F = (6.67430 × 10^-11 Nm^2/kg^2 * 11 kg * 0.07 kg) / (0.08 m)^2
Simplifying the equation:
F = (6.67430 × 10^-11 Nm^2/kg^2 * 0.77 kg) / (0.008 m^2)
F = 5.84354 × 10^-9 N
Therefore, each lead ball exerts a gravitational force of approximately 5.84 × 10^-9 Newtons on the other.