posted by Z32 on .
Evaluate the following limits.
lim as x approaches infinity 6/e^x + 7=____?
lim as x approaches negative infinity 6/e^x+7=____?
for the first
as x gets larger, 6/e^x gets closer to zero
so the limit is 0+7 = 7
for the second, remember that 1/a^-n = a^n
so for huge negative values of x, 6/e^x becomes "huge"
so for the second, it is undefined (infinitely large)