Posted by Anonymous on Tuesday, September 29, 2009 at 9:19am.
First use school boy logic to dismiss any silly answers. If the temperature has dropped then the new pressure must be less than 50.0 atm. Thus we can dismiss 105 atm, and 54.9 atm.
Use P1/T1=P2/T2
or by inspection the temperature has dropped by approximately a factor of 2 (from 573 K to 273 K) so the pressure is approximately half the starting pressure of 50 atm. Thus the answer must 23.8 atm.
[and no calculator needed!]
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