Posted by **Elisa** on Tuesday, September 29, 2009 at 5:38am.

Write the equation in standard form for the line that passes through (6, -1) and (10,-*)

So far I have -8-1 is -9 and 10-6 is 4, is the -9 correct?

Then y plus 10 equals 9/4(x - 8)

Then multiply by 2 so 2y plus 20 equals 18/4x - 146/4

Is this correct so far?

- Algebra 1 -
**Reiny**, Tuesday, September 29, 2009 at 8:21am
I replied to one of your previous questions which is almost identical to this one, but apparently you did not look at it.

http://www.jiskha.com/display.cgi?id=1254199568

anyway...

first of all, you have an error in your calculation of slope.

slope = (-8 - (-1))/(10 - 6)

= -7/4

then, using (10,-8)

y - (-8) = (-7/4)(x-10)

y + 8 = (-7/4)(x-10)

multiply both sides by 4 to get rid of fractions...

4y + 32 = -7(x-10)

4y + 32 = -7x + 70

7x + 4y = 38

I usually check using the point NOT used to find the equation, the (6,-1)

Left Side = 7(6) + 4(-1)

= 42 - 4

= 38

= Right Side !

You are making errors in subtracting integers.

- Algebra 1 -
**Elisa**, Tuesday, September 29, 2009 at 8:36am
yes, I did see the reply earlier. However, I'm still having trouble figuring out how to do the work.

thanks for your help.

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