Posted by Elisa on Tuesday, September 29, 2009 at 5:38am.
Write the equation in standard form for the line that passes through (6, -1) and (10,-*)
So far I have -8-1 is -9 and 10-6 is 4, is the -9 correct?
Then y plus 10 equals 9/4(x - 8)
Then multiply by 2 so 2y plus 20 equals 18/4x - 146/4
Is this correct so far?
Algebra 1 - Reiny, Tuesday, September 29, 2009 at 8:21am
I replied to one of your previous questions which is almost identical to this one, but apparently you did not look at it.
first of all, you have an error in your calculation of slope.
slope = (-8 - (-1))/(10 - 6)
then, using (10,-8)
y - (-8) = (-7/4)(x-10)
y + 8 = (-7/4)(x-10)
multiply both sides by 4 to get rid of fractions...
4y + 32 = -7(x-10)
4y + 32 = -7x + 70
7x + 4y = 38
I usually check using the point NOT used to find the equation, the (6,-1)
Left Side = 7(6) + 4(-1)
= 42 - 4
= Right Side !
You are making errors in subtracting integers.
Algebra 1 - Elisa, Tuesday, September 29, 2009 at 8:36am
yes, I did see the reply earlier. However, I'm still having trouble figuring out how to do the work.
thanks for your help.
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