A wire carries a 15 microampere current.
How many electrons pass a given point on the wire in 1.0 ?
1.0 what? seconda?
In one second, 15*10^-6 Coulombs of charge flows. Divide that by the electron charge (1.6*10^-19 C) for the number of electrons that flow.
It will be roughly 10^14
To determine the number of electrons passing a given point on the wire in 1.0 second, we need to know the charge carried by each electron and the time it takes for an electron to pass that point.
The charge carried by each electron is 1.6 x 10^-19 coulombs (C). This value is obtained from the elementary charge of an electron.
To find the time it takes for an electron to pass the given point, we can use the current equation:
current (I) = charge (Q) / time (t)
Rearranging the equation, we have:
time (t) = charge (Q) / current (I)
Plugging in the given values:
charge (Q) = 1.6 x 10^-19 C (elementary charge)
current (I) = 15 x 10^-6 A (15 microamperes) = 15 x 10^-6 C/s
t = (1.6 x 10^-19 C) / (15 x 10^-6 C/s)
Calculating the value, we get:
t ≈ 1.07 x 10^-14 s (seconds)
Now we can find the number of electrons passing the given point in 1.0 second:
Number of electrons = (1.0 s) / (1.07 x 10^-14 s)
Calculating the value, we get:
Number of electrons ≈ 9.35 x 10^13 electrons (rounded to two decimal places)
Therefore, approximately 9.35 x 10^13 electrons pass a given point on the wire in 1.0 second.
To determine the number of electrons passing through a wire in a given time, we need to use the equation relating current, charge, and time. The equation is:
Q = I * t
Where:
Q is the charge in coulombs (C)
I is the current in amperes (A)
t is the time in seconds (s)
First, we need to convert the current from microamperes (μA) to amperes (A). Since 1 microampere is equal to 1 x 10^-6 amperes, we can rewrite the current as:
I = 15 x 10^-6 A
Next, we need to determine the charge transferred in 1 second. Since the current is constant, we can calculate the charge using the equation:
Q = I * t
Plugging in the values:
Q = (15 x 10^-6 A) * (1 s)
Calculating the charge:
Q = 15 x 10^-6 C
Now, to find the number of electrons passing through the wire, we need to know the charge of a single electron. The elementary charge, denoted as e, is the charge of a single electron and is approximately equal to 1.6 x 10^-19 C.
Dividing the charge transferred by the elementary charge will give us the number of electrons:
Number of Electrons = (15 x 10^-6 C) / (1.6 x 10^-19 C)
Calculating the number of electrons:
Number of Electrons ≈ 9.375 x 10^13
Therefore, approximately 9.375 x 10^13 electrons pass through the given point on the wire in 1.0 second.