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January 28, 2015

January 28, 2015

Posted by **lacrsha** on Monday, September 28, 2009 at 9:08pm.

- algebra -
**MathMate**, Monday, September 28, 2009 at 9:40pmThe y-intercept of the line

L1 : x+4y=12 can be found by putting the equation in slope-intercept form,

L1 : y = -(1/4)x + 3

The intercept is thus +3, and the point of intercept is (0,3).

The linear function therefore passes through the points P1(0,3) and P2(5,4).

The slope m,can be found by

m=(y2-y1)/(x2-x1) as long as x2≠x1.

The line passing through the two given points is

L2 : (y-y1)/(y2-y1)=(x-x1)/(x2-x1)

where y2≠y1 and x2≠x1.

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