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Posted by on Monday, September 28, 2009 at 7:02pm.

Write the balanced chemical equation for each reaction:

K2MnO4(aq)+H2SO4(aq)+NaHSO3(aq)= ?

K2MnO4(aq)+NaOH(aq)+NaHSO3(aq)= ?

start with the net ionic equations.

  • 12 chemistry - , Monday, September 28, 2009 at 7:26pm

    Do you mean K2MnO4 or KMnO4? If K2MnO4 then Mn is +6. If KMnO4 then Mn is +7.
    In acid solution, Mn goes to +2 (Mn^+2), in basic solution to MnO2. S in HSO3^- goes to +6 (SO4^-2) in acid or basic solution.

  • 12 chemistry - , Monday, September 28, 2009 at 7:28pm

    yeah sorry it was KMnO4

  • 12 chemistry - , Monday, September 28, 2009 at 7:30pm

    i just still have no idea what the full equation would look like...

  • 12 chemistry - , Monday, September 28, 2009 at 7:59pm

    You do the half equations.
    MnO4^- ==> Mn^+2
    HSO3^- ==> SO4^-2

    For example, the permanganate half equation is
    5e +MnO4^- + 8H^+ ==> Mn^+2 + 4H2O

    Do the HSO3^-, multiply by a number to make the electrons equal, then add the two equations. This gives you the ionic equation for that reaction. Then add K^+ and Na^+ as needed for the positive charges and add SO4^-2 (from H2SO4) to balance those charges.

  • 12 chemistry - , Monday, September 28, 2009 at 8:19pm

    ok thankyou

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