Posted by **Dreskillz89** on Monday, September 28, 2009 at 4:23pm.

A ball is thrown upward off the top of a 30-meter high building. 10 meters below the top of the roof, is the top of a window, which is 2 meters high. How long (time) does it take for the ball to pass from top to bottom of the window?

What I have so far is:

-10 = v(initial) t - 4.9 t^2

-12 = v(initial) t - 4.9 t^2

How do I solve this question if I don't even have initial velocity?

- physics - add.info. required -
**MathMate**, Monday, September 28, 2009 at 7:49pm
"How do I solve this question if I don't even have initial velocity? "

You are quite right. You need additional information, for example maximum height attained, time it took to come back to the top of the roof, initial velocity, etc.

On the other hand, the height of the building (30m) is immaterial.

## Answer this Question

## Related Questions

- Physics - Standing on the top ledge of a 55 m high building you throw a ball ...
- Physics - A steel ball is dropped from a building's roof and passes a window, ...
- Physics - Standing on the top ledge of a 55 m high building you throw a ball ...
- physics - A tennis ball is thrown horizontally at a speed of 10 m/s from the top...
- Algebra II - A rock is thrown upward with a velocity of 19 meters per second ...
- algebra - A rock is thrown upward with a velocity of 15 meters per second from ...
- Algebra II - A rock is thrown upward with a velocity of 28 meters per second ...
- Algebra II - A rock is thrown upward with a velocity of 28 meters per second ...
- Physics - The ball is thrown upward with a speed of 38.0m/s from the top of a ...
- Algebra - a rock is thrown upward with a velocity of 20 meters per second from ...

More Related Questions