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March 30, 2017

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the perimeter of a rectangle is 224 incles. the length exceeds the width by 64 inces. find the length and the width.


the length is _____ inches

and

the width is _____ inches

  • algebra 1 - ,

    Let
    L=length
    W=width = L-64
    Perimeter = 224 = 2(L+W) = 2(L+L-64)
    Solve for L.

  • algebra 1 - ,

    A=1/2h(b1+b2)
    solve for b

  • algebra 1 - ,

    "A=1/2h(b1+b2)
    solve for b"
    I do not see the variable b in the expression: b1 and b2 are different variables than b.
    In any case, I suggest you start a new thread for a new question.

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