Posted by **spirit73** on Monday, September 28, 2009 at 3:06pm.

the perimeter of a rectangle is 224 incles. the length exceeds the width by 64 inces. find the length and the width.

the length is _____ inches

and

the width is _____ inches

- algebra 1 -
**MathMate**, Monday, September 28, 2009 at 6:29pm
Let

L=length

W=width = L-64

Perimeter = 224 = 2(L+W) = 2(L+L-64)

Solve for L.

- algebra 1 -
**Elanea**, Monday, September 28, 2009 at 6:43pm
A=1/2h(b1+b2)

solve for b

- algebra 1 -
**MathMate**, Monday, September 28, 2009 at 7:01pm
"A=1/2h(b1+b2)

solve for b"

I do not see the variable b in the expression: b1 and b2 are different variables than b.

In any case, I suggest you start a new thread for a new question.

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