Find the equation of the circle when the center is at the origin and the radius is 6.
Thanks!
X^2 + Y^2 = 36
Here is a very good site to read about how to write the equation of a circle.
http://www.analyzemath.com/CircleEq/CircleEq.html
Raul and Luis were brothers who decided to go into business mowing lawns. thier parents told them they could use the family truck but they would need to buy their own equipment since the family lawn mower was barely working. they bought ywo lawn mowers for $150.00 each and had 300 flyers made for 12 cents each.
they agreed to work together on every job and split the money evenly. After distributing flyers to all homes around them, they waited for all the calls. They soon soon had so much business they could hardly keep up.they charged $30 for 1/4 acre lots and $60 for 1/2 acre lots.
they had to buy a trimmer for $30 and a hedge trimmer for $20.
A receipt book and an appointment book for $12.
How many 1/4 acre lots will they have to cut to earn $500 each after they pay their expenses? They estimate they spent about $1.00 on gas for each lawn.
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To find the equation of a circle when the center is at the origin, we use the distance formula. The distance formula is given by:
Distance = √((x2 - x1)^2 + (y2 - y1)^2)
Since the center of the circle is at the origin (0, 0), the coordinates (x1, y1) are (0, 0). Let's assume a generic point on the circle with coordinates (x, y).
Using the distance formula, we get:
√((x - 0)^2 + (y - 0)^2) = 6
Simplifying this equation, we get:
√(x^2 + y^2) = 6
Since we are looking for the equation of a circle, we need to remove the square root by squaring both sides of the equation:
x^2 + y^2 = 6^2
Simplifying further, we get:
x^2 + y^2 = 36
Therefore, the equation of the circle with a center at the origin (0, 0) and a radius of 6 is x^2 + y^2 = 36.