Chemistry II
posted by Mandy on .
Acetone, C3H6O, is the main ingredient of nail polish remover. A solution is made up by adding 35.0mL of acetone(d=0.790g/mL) to 50.0mL of ethyl alcohol,C2H6O(d=0.798 g/mL). Assume that the volumes are additive. From this information calculate the molarity of acetone in the solution.
Ok is the mole of C3H6O 58.09mol, and if so, what do I do next?

The molar mass of acetone is correct.
Here is what you do.
Convert density acetone and density ethyl alcohol (together with volume) to grams,
density = mass x volume.
mass = density/volume. You are given the density of each and the volume of each. Determine mass of each.
Next, convert grams of each to moles.
moles = grams/molar mass.
Then molarity = moles/L and L = 50 mL + 35 mL = 85 mL = 0.085 L. 
If you do everything I suggested, you will do more than necessary. I just worked the problem. You don't need the mass of ethyl alcohol nor the moles ethyl alcohol.

correction to the formula of density. density is equal to the ratio mass and volume, that is
d=m/v
m=d*v