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February 1, 2015

February 1, 2015

Posted by **steph** on Sunday, September 27, 2009 at 10:46pm.

- physics -
**drwls**, Monday, September 28, 2009 at 6:23amYou gave the details but failed to ask the question.

If you want to know how far away from the (vertical) cliff the stone hits the water, multiply 11 m/s by the time T that it takes the stone to fall to the water's surface.

(g/2)T^2 = 47 m

T = sqrt (2*47/9.8)= 3.1 s

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