this is a question for a lab experiment...in the lab we got 2 empty vials and were supposed "eyeball" 1.0g of NaCl into each of the vials using a vial with NaCl in it already as a sample. Then we weighed the filled vials on analytical balance and recorded weight. Then we emptied the vials and weighed them on the analytical balance.
The question is:
why is the "empty" vial weighed after pouring the sodium chloride out of the vial, instead of before putting the sodium chloride into the vial?
You need to tell me more about the experiment. Perhaps another volunteer has some experience with an experiment of this type and can chime in. What did you do with the data? What was the purpose of the experiment?
If you wanted to know what amount of sodium chloride was delivered into another container, you would weigh the vial with the salt in it, then weigh the "empty" container which may have traces of salt stuck in it.
wtf u sayin dawg
I got the biggest "chemistry set" ever
y'all gonna get beat down in mah hood
The "empty" vial is weighed after pouring the sodium chloride out of the vial instead of before putting the sodium chloride into the vial in order to determine the actual weight of the NaCl.
Here's the step-by-step explanation:
1. Initially, you have two empty vials. To measure exactly 1.0g of NaCl, you can use a vial with NaCl already in it as a sample.
2. First, you weigh the vial with the NaCl sample on an analytical balance and record its weight. Let's call this weight A.
3. Next, you transfer the NaCl from the sample vial into each empty vial. Each vial should now contain approximately 1.0g of NaCl.
4. After transferring the NaCl, you weigh the vials, one at a time, on the analytical balance and record their weights. Let's call these weights B and C.
5. Now, in order to determine the actual weight of the NaCl, you need to eliminate the weight of the vials. To do this, you weigh the "empty" vial by pouring out the NaCl from it and then weigh it again on the analytical balance. Let's call this weight D.
6. Finally, you calculate the actual weight of the NaCl for each vial. This can be done by subtracting the weight of the "empty" vial (weight D) from the previously recorded weights of the vials containing NaCl (weights B and C). Hence, the actual weight of NaCl for the first vial is B - D and for the second vial is C - D.
By weighing the "empty" vial after pouring the sodium chloride out, you can determine the weight of the vial itself and subtract it from the measured weight of the vial with NaCl to obtain the accurate weight of the NaCl. This allows you to take the weight of the vial into account when calculating the actual weight of the substance you are interested in.