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April 19, 2014

April 19, 2014

Posted by **CM** on Sunday, September 27, 2009 at 8:51pm.

I don't know how to standardize this without either one (the mean or standard deviation) if that is even what I have to do?

- Stats -
**jim**, Sunday, September 27, 2009 at 9:17pmGiven the mean and atsndard deviation, you can find the score for an area under the curve, but working backward, given two percentiles and scores, you can work that in reverse.

Reading off the numbers from a z-table (I hope you don't have to work it out from the equation!) I see that 90% equates to 1.28 SD away from the mean and 20% equates to 0.84 SD from the mean. (We don't have to worry about sign, since the curve is symmetric.)

So 9 months, being the difference between 13 and 22, constitutes a total of 2.32 SD. Does that give you enough to go on?

- Stats -
**CM**, Sunday, September 27, 2009 at 9:34pmI'm not sure where you get the 2.32 SD from? And would I use the percentages or months in the calculation with what mean?

- Stats -
**jim**, Sunday, September 27, 2009 at 9:55pm90% is 22 months, is 1.28 SD from the mean.

20% is 13 months, is .84 SD in the opposite direction from the mean.

Thus, a difference of (22 - 13) months is equivalent to to (1.28 - (-.84)) SD.

- Stats -
**CM**, Sunday, September 27, 2009 at 10:06pmThat equals 2.12. So, I use the z-score from the 20% and 90% and the 2.12 SD, but what do I use for the two means or top numbers when standardizing?

- Stats -
**jim**, Monday, September 28, 2009 at 8:01amSorry about my mental arithmetic error. :-)

So 9 months is 2.12 SD. so 1SD is 4.25 months.

1.28 SD is then 5.44 months from the mean, so the mean is 22 - 5.44.

Check: working it the other way .84 is 3.57 months, so the mean is 13 + 3.57.

Do those agree? Yes, our mean is 16.57, with an SD of 4.25.

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