Homework Help: physics

Posted by help on Sunday, September 27, 2009 at 8:27pm.

Cars A and B are racing each other along a straight path in following manner: Car A has head start and is a distance dA beyond starting line at t=0. The starting line is at x=o. Car A travels at constant speed vA. Car B starts at starting line but has better engine than car A and travels at constant speed vB (which is greater than vA). How long after Car B started the race will Car B catch up with Car A? How far from Car B's starting line will the cars be when Car B passes Car A?

physics - MathMate, Monday, September 28, 2009 at 8:25am
To summarize:
At t=0
car A: x=dA, speed=vA
car B: x=0, speed=vB
When will car B overtake car A and where.

Distance to catch-up = dA
difference in speed = (vB-vA)
Time to catch up, T = dA/(vB-vA)
location where the two cars are side-by-side
= T*vB
= dA*vB/(vB-vA)

Answer this Question

Related Questions

physics - Cars A and B are racing each other along a straight path in following ...
physics - Cars A and B are racing each other along the same straight road in the...
math - distance = rate x time or d = r*t car traveling 40 mi/hr goes 40 mi/hr x ...
Physics - Two cars are traveling along a straight line in the same direction, ...
physics - Two cars are traveling at the same constant speed v. Car A is moving ...
physics - Two cars are initially moving at constant speeds of 50 m/s (first car...
Physics - Two cars travel westward along a straight highway, one at a constant ...
Physics - Two cars are traveling along a straight line in the same direction, ...
Physics - Two cars are traveling along a straight line in the same direction, ...
physics - Two cars start from rest at the same location and at the same instant ...

For Further Reading

First Name:
School Subject:
Answer: