Acetone, C3H6O, is the main ingredient of nail polish remover. A solution is made up by adding 35.0mL of acetone(d=0.790g/mL) to 50.0mL of ethyl alcohol,C2H6O(d=0.798 g/mL). Assume that the volumes are additive. From this information calculate the molarity of acetone in the solution.

My answer was 2.3g, but it was wrong.

Ok, given the volume and density, you can determine the grams of each compound present.

That leaves you with needing to find the moles of acetone in the solution of 85mL, or 0.085L.

Now, what quantity can you calculate that would relate grams and moles? Think periodic table.

Once you know the number of moles you can calculate the molarity.

Molarity= mole solute / L of solution

To calculate the molarity of acetone in the solution, you first need to determine the moles of acetone present in the solution. Here's how you can do it:

1. Calculate the mass of acetone added to the solution:
Mass = volume × density = 35.0 mL × 0.790 g/mL = 27.65 g

2. Convert the mass of acetone to moles by using its molar mass (58.08 g/mol):
Moles of acetone = Mass / Molar mass = 27.65 g / 58.08 g/mol ≈ 0.476 moles

3. Compute the total volume of the solution:
Total volume = volume of acetone + volume of ethyl alcohol = 35.0 mL + 50.0 mL = 85.0 mL

4. Convert the total volume to liters:
Volume in liters = Total volume / 1000 = 85.0 mL / 1000 = 0.085 L

5. Finally, calculate the molarity of acetone using the moles of acetone and the volume in liters:
Molarity = Moles of solute / Volume of solution in liters = 0.476 moles / 0.085 L ≈ 5.6 M

Therefore, the molarity of acetone in the solution is approximately 5.6 M.