A man of mass 82 kg is using crutches. the crutches make an angle of 26 degrees with the vertical. Half the person's weight is supported by the crutches. Assuming that the person is at rest, find the magnitude of the force supported by each crutch.
the way i did this question was first i divided the weight by 2 since only half the weight is supported by the crutches and drew the free body diagram according to that. Now the force of the crutches is at an angle so we have to use vector components. I just used the y component of this force which was (F_T)(cos26). Also, the force of gravity is also acting on the body's weight, which came out to be: F_g = (41)(-9.8).
Fnet y = (F_g) + (F_T)(cos26)
i got my answer for F_T to be 447 N.
Can someone please confirm if this is the right way to do this question and whether this answer is correct? Thanks in advance!
physics - MathMate, Monday, September 28, 2009 at 9:06am
You have the good approach in isolating the free-body diagram, and taking advantage of symmetry.
The answer is correct.
physics - JOHN, Monday, September 28, 2009 at 8:48pm
SO is the answer for each of the crutches 45.243N?
physics - Karina, Monday, September 28, 2009 at 10:59pm
Can you elaborate on that. I still don't know how you calculated and got 447 N