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October 2, 2014

October 2, 2014

Posted by **Hannah** on Sunday, September 27, 2009 at 5:43pm.

the way i did this question was first i divided the weight by 2 since only half the weight is supported by the crutches and drew the free body diagram according to that. Now the force of the crutches is at an angle so we have to use vector components. I just used the y component of this force which was (F_T)(cos26). Also, the force of gravity is also acting on the body's weight, which came out to be: F_g = (41)(-9.8).

So,

Fnet y = (F_g) + (F_T)(cos26)

i got my answer for F_T to be 447 N.

Can someone please confirm if this is the right way to do this question and whether this answer is correct? Thanks in advance!

- physics -
**MathMate**, Monday, September 28, 2009 at 9:06amYou have the good approach in isolating the free-body diagram, and taking advantage of symmetry.

The answer is correct.

Good work!

- physics -
**JOHN**, Monday, September 28, 2009 at 8:48pmSO is the answer for each of the crutches 45.243N?

- physics -
**Karina**, Monday, September 28, 2009 at 10:59pmCan you elaborate on that. I still don't know how you calculated and got 447 N

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