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A particle experiences a constant acceleration that is south at 2.50 meters per second squared. At t=0, its velocity is 40.0 meters per second east. What is its velocity at t=8.00 seconds?

  • physics -

    The acceleration is due south, so the east-west component (40 m/s) is not altered.
    For the north-south component, at t=0,
    initial velocity = 0 m/s
    after 8 seconds,
    velocity v=0+(-2.5)8 = -20 m/s (<0 for south)
    Velocity = (40,-20) m/s
    Magnitude = √(40²+20²)
    =44.72 m/s
    atan(-20/40)=-26.57°, or
    26.57° south of east.

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