Posted by **Need Help** on Sunday, September 27, 2009 at 3:36pm.

A particle experiences a constant acceleration that is south at 2.50 meters per second squared. At t=0, its velocity is 40.0 meters per second east. What is its velocity at t=8.00 seconds?

- physics -
**MathMate**, Sunday, September 27, 2009 at 5:21pm
The acceleration is due south, so the east-west component (40 m/s) is not altered.

For the north-south component, at t=0,

initial velocity = 0 m/s

after 8 seconds,

velocity v=0+(-2.5)8 = -20 m/s (<0 for south)

Velocity = (40,-20) m/s

Magnitude = √(40²+20²)

=44.72 m/s

direction:

atan(-20/40)=-26.57°, or

26.57° south of east.

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