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Posted by **Dreskillz89** on Sunday, September 27, 2009 at 12:02pm.

How do I calculate the tension T in the rope if the gymnast hangs motionless on the rope?

Also, what if the gymnast climbs the rope at a constant rate. How would I calculate that?

Thanks in advance!

- physics -
**giugui**, Wednesday, September 30, 2009 at 11:17pmuiguiiu

- physics -
**daniel**, Tuesday, September 28, 2010 at 7:59pmF=ma , T=ma

T = (61kg)(9.81m/s^2) = ? N (do the math)

Constant rate would mean there is no acceleration, so T = ma + m(0)== ma

Furthermore, if the gymnast is climbing up at a certain acceleration, lets say 2.1 m/s^2, use the rate at which they climb for the acceleration in the second have of the equation. Add it because they are going up, + acceleration.

T = ma1 + ma2 == 63x9.81 + 63x2.1

If the gymnast is going down, use the same formula but subtract.

T = ma1 + ma2 == 63x9.81 - 63x2.1

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