Saturday

August 2, 2014

August 2, 2014

Posted by **Marrion** on Sunday, September 27, 2009 at 2:11am.

I don't know what i'm supposed to do, and i dont come to an answer! Help, thanks!

my workings:

tan(45+x)= (1+tanx)/(1-tanx)

a/b = (1+tanx)/(1-tanx)

a(1-tanx)=b(1+tanx)

i square both sides...

a^2(1-tanx)^2 = b^2(1+tanx)^2

a^2 + b^2 = 2

a^2 = 2 - b^2

substitute:

(2-b^2)(1-tanx)^2 = b^2(1+tanx)^2

I don't know if im on the right track, but i don't seem to come to an answer when i expand the whole equation!

- Trigonometry -
**MathMate**, Sunday, September 27, 2009 at 8:48amFrom:

a(1-tanx)=b(1+tanx)

multiply both sides by cos(x) to get

a(cos(x)-sin(x))=b(cos(x)+sin(x))

Now square and simplify. The product terms will cancel out after you substitute b²=(2-a²) to give you a in terms of sin(x) and cos(x).

You can do similarly for b.

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