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November 28, 2014

November 28, 2014

Posted by **joe** on Saturday, September 26, 2009 at 11:20pm.

14/(x^2 - 361) <-- this is all under a square root..

i have attempted this so many times and have not found the correct answer yet. how do i solve the domain when it is a square root function with a denominator???? please help!

thanks

- calculus HELP -
**Reiny**, Saturday, September 26, 2009 at 11:30pmTwo conditions are the problem here:

1. We cannot divide by zero

2. We cannot take the square root of a negative.

so 14/√(x^2 - 361)

= 14/√[(x+19)(x-19)]

so clearly x cannot be ± 19

secondly, wouldn't the number under the root sign be negative for all values between 1- and +19

so the domain is

x > 19 OR x < -19 , x is a real number.

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