Posted by joe on .
how do you find the domain of the function::
14/(x^2  361) < this is all under a square root..
i have attempted this so many times and have not found the correct answer yet. how do i solve the domain when it is a square root function with a denominator???? please help!
thanks

calculus HELP 
Reiny,
Two conditions are the problem here:
1. We cannot divide by zero
2. We cannot take the square root of a negative.
so 14/√(x^2  361)
= 14/√[(x+19)(x19)]
so clearly x cannot be ± 19
secondly, wouldn't the number under the root sign be negative for all values between 1 and +19
so the domain is
x > 19 OR x < 19 , x is a real number.