Saturday

December 20, 2014

December 20, 2014

Posted by **Marrion** on Saturday, September 26, 2009 at 2:53am.

Ok, i've tried to find a factor of the quadratic function using trial and error.

Let f(x) = 2x^3-3x^2-3x-5

f(1) is not equals to 0

f(-1) is not equals to 0

...

and i cant find a number that would equate the function to 0. So i'm stuck and i dont know how i should go about doing this question. Help!

- ?? Maths?? -
**Marth**, Saturday, September 26, 2009 at 10:12amUse long division: divide 2x^3-3x^2-3x-5 by x^2+bx+c

You want the remainder to be 0, so you should be able to solve for b and c after you divide.

**Answer this Question**

**Related Questions**

math - solve the equation x^3-5x^2-4x+20=0 I need a hint on how to solve this ...

Maths - The question is "Show that z-2 is a factor of P(z)= z^3+mz^2+(3m-2)z-10m...

Math - How can I find the point of intersection of the graphs x^2=y=4 and 2x-y=1...

Maths (factor theorem) - 9x^2 6xy 4y^2 is a factor of 27x^3 - 8y^3, find the ...

help with solving - x^2+(x-2)^2 = (2x-6)^2 solve for x. thanks so much. Please ...

Maths - It is given a quadratic function y=a(x-h)62+k.If its graph is a parabola...

Pre Calculus - using the factor theorem to show that x-c is a factor of P(X) for...

Factoring Polynomials - The book says: Find three different values that complete...

Algebra - I'm trying to solve x^3-3x^2-x+3 is less than zero. Except, I'm not ...

Factor - How do I factor these: 2x2 - 16x + 30 4x^2-9 x^2-5x 5x^2-26x+5 25x^2+4 ...