# Trigo

posted by
**Marrion** on
.

Given that a^2+b^2=2 and that (a/b)= tan(45degee+x), find a and b in terms of sinx and cosx.

I don't know what i'm supposed to do, and i don't come to an answer! Help, thanks!

my workings:

tan(45+x)= (1+tanx)/(1-tanx)

a/b = (1+tanx)/(1-tanx)

a(1-tanx)=b(1+tanx)

i square both sides...

a^2(1-tanx)^2 = b^2(1+tanx)^2

a^2 + b^2 = 2

a^2 = 2 - b^2

substitute:

(2-b^2)(1-tanx)^2 = b^2(1+tanx)^2

I don't know if im on the right track, but i don't seem to come to an answer when i expand the whole equation!