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physics

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a boy throws a stone straight upward with an initial speed of 15.0m/s. what mazimum height will the stone reach before falling back down.

  • physics -

    Can you use V^2 = Vo^2 + 2a*distance and set V^2 = 0?

  • physics -

    One method to solve this is conservation of energy.
    initial kinetic energy = final potential energy
    let m = mass of stone
    let g = acceleration of gravity
    let v = initial velocity
    let h = maximum height
    (1/2)mv^2 = mgh
    So,
    v^2 = 2gh
    h = (v^2)/g

  • physics -

    23

  • physics -

    22.95

  • physics -

    final velocity squared = initial velocity squared + 2(acceleration)(displacement)

    0 = (15*15) + 2(9.8)x
    0 = 225 + 19.6x
    -225 = 19.6x
    x= 11m

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