Wednesday

April 1, 2015

April 1, 2015

Posted by **allison** on Thursday, September 24, 2009 at 10:32pm.

1) Given f(x) = (x^2 - 2x + 1) for x does not equal 1 and (k) for x = 1

Determine the value of k for which f is continuous for all real x.

a) 0

b) 1

c)2

d)3

e)none of the above

i think the anser is a but i'm really not sure how to solve this.

2) The graph of y = sinx / x has

I. a vertical asymptote at x=0

II. a horizontal asymptote at y=0

III. an infinite number of zeros

a) I only

b) II only

c) III only

d) I and II only

e) II and III only

I think the answer is d but I'm not positive.

If someone could please help me that would be greatly appreciated! :)

- calculus -
**Reiny**, Thursday, September 24, 2009 at 11:38pmyou are right on #2

as x gets larger, you are dividing by an increasingly larger number, so the result goes to zero

also sin(x) fluctuates between +1 and -1 so crosses the x-axis again and again.

#1 ?

are you sure you typed the function correctly?

The way you have it, it is simply a parabola, which would be continuous for every x.

Where does the k come in?

The question is quite confusing.

- calculus -
**Hillary**, Friday, September 25, 2009 at 12:30amHaha I know! I did type it in right... It really is confusing because I don't have a clue what to do with the k!

But thank you for your help on question #2!! :)

**Answer this Question**

**Related Questions**

calculus - Having trouble with a section in my summer assaignment, and my ...

Calculus - Would you be able to help me with a couple of questions? thanks in ...

To Derr - You have made a couple of uncalled for comments to a couple of ...

APA Format - Hi i have a couple of dumb questions :) I know the good websites ...

Music - I have a couple of questions... 1. I have to transpose a musical piece ...

math - I am answering questions concerning equity, the problem is a story ...

To LaShondra - I've deleted your last two posts containing 45 multiple choice ...

calculus - where is f(x)=12cos(3x) equal to zero. so far i have pi/2+n2pi.. i am...

ALL OF JISHKA STAFF - Hello I had a couple of questions and was woundering if ...

Applied Calculus-Question for Damon - Hi, I have two other questions for Applied...