Wednesday
November 26, 2014

Homework Help: Pre-Calc

Posted by MUFFY Question has been fixed on Thursday, September 24, 2009 at 8:59pm.

The height s of a ball, in feet, thrown with an initial velocity of 112 feet per second from an initial height of 20 feet is given as a function of time t (in seconds) by
s(t)= -16t^2+112t+20. What is the maximum height of the ball? At what time does the maximum height occur?

I know how to find the maximum height. You find the vertex which is 3.5 then plug it back into the original equation.

Now, when it says what time, I am not sure if it wants the vertex or should I use the quadratic to solve it?

Please help.

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