Saturday

March 28, 2015

March 28, 2015

Posted by **MUFFY Question has been fixed** on Thursday, September 24, 2009 at 8:59pm.

s(t)= -16t^2+112t+20. What is the maximum height of the ball? At what time does the maximum height occur?

I know how to find the maximum height. You find the vertex which is 3.5 then plug it back into the original equation.

Now, when it says what time, I am not sure if it wants the vertex or should I use the quadratic to solve it?

Please help.

- Pre-Calc -
**MathMate**, Thursday, September 24, 2009 at 9:23pmThe maximum height

*is*the vertex.

This would be an application of completing the squares to convert the function into the standard form:

s(t)=a(t-h)²+k

where t=h at the vertex (3.5) and

k=maximum height (216 above datum)

- Pre-Calc -
**MUFFY Question has been fixed**, Thursday, September 24, 2009 at 9:29pmOk thanks.

- Pre-Calc -
**MathMate**, Thursday, September 24, 2009 at 9:54pmYou're welcome!

**Answer this Question**

**Related Questions**

ap calculus - The height s of a ball, in feet, thrown with an initial velocity ...

Algebra - The height of a ball thrown directly up with a velocity of 40 feet per...

Algebra - THe function h(t)=-16t^2+v0t+h0 describes the height in feet above the...

Algebra - THe function h(t)=-16t^2+v0t+h0 describes the height in feet above the...

pre-calc - Physics: a ball is thrown vertically upward with an initial velocity ...

Pre Calc - Alice throws a ball straight up with an initial speed of 40 feet per ...

Pre calc - Alice throws a ball straight up with an initial speed of 40 feet per ...

algebra - The height in feet of a projectile with an initial velocity of 32 feet...

Math - The height of a golf ball that is hit into the air with an initial ...

algebra - suppose a ball is thrown upward from a height of 4.5 feet with an ...