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December 20, 2014

December 20, 2014

Posted by **MUFFY Question has been fixed** on Thursday, September 24, 2009 at 8:59pm.

s(t)= -16t^2+112t+20. What is the maximum height of the ball? At what time does the maximum height occur?

I know how to find the maximum height. You find the vertex which is 3.5 then plug it back into the original equation.

Now, when it says what time, I am not sure if it wants the vertex or should I use the quadratic to solve it?

Please help.

- Pre-Calc -
**MathMate**, Thursday, September 24, 2009 at 9:23pmThe maximum height

*is*the vertex.

This would be an application of completing the squares to convert the function into the standard form:

s(t)=a(t-h)²+k

where t=h at the vertex (3.5) and

k=maximum height (216 above datum)

- Pre-Calc -
**MUFFY Question has been fixed**, Thursday, September 24, 2009 at 9:29pmOk thanks.

- Pre-Calc -
**MathMate**, Thursday, September 24, 2009 at 9:54pmYou're welcome!

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