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April 18, 2014

Homework Help: Physics - ice to liquid

Posted by Ceres on Thursday, September 24, 2009 at 5:48pm.

Fifty grams of hot water at 80oC is poured into a cavity in a very large block of ice at 0oC. The final temperature of the water in the cavity is then 0oC. Show that the mass of ice that melts is 50 g.

To melt ice to 50g of water, I think that it will take:
50g(334J/g) = 167,000J

When cooling, the hot water should release:

Specific heat capacity of water(ΔT)(grams of water)(conversion to J from calories) = J released by cooling

(.5cal/g*oC)(80oC)(50g)(4.18J/cal) = 8360J

This is only about half of the energy that is needed to convert the ice to water, so I am missing something. Any ideas?

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