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Posted by Anonymous on Thursday, September 24, 2009 at 3:36pm.

[2x-12]/[3x-6] * [x^2-4]/[x^2-36] * [3x+18]/[4x+8] Would the solution be (x-4) over 2(x-2)(x+2)?

You seem to have written (x^2 - 4) as (x-4) at some point.

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