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November 26, 2014

November 26, 2014

Posted by **Megan** on Wednesday, September 23, 2009 at 11:27pm.

- Physics -
**MathMate**, Thursday, September 24, 2009 at 12:18amNote: the two blocks are suspended vertically by the string passing over a pulley.

m1=3.4 kg

m2=9.1 kg

H=1.3 m

Let tension = T

acceleration = a

acceleration due to gravity = g

Consider block 1:

Net upward force, F1 = T-m1.g

F1.a = T-m1.g

Consider block 2:

Net downward force, F2 = m2.g - T

F2.a = m2.g - T

Solve for T and A.

Use kinematics equation to solve for time: H=v0.t + (1/2)at²

where v0 = initial velocity=0 m/s, and

t=time in seconds.

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