posted by Mia on .
Paleontologists estimate that if a Tyrannosaurus rex were to trip and fall, it would have experienced a force of approximately 260,000 N acting on its torso when it hit the ground.
Assuming the torso has a mass of 3800 kg , find the magnitude of the torso's upward acceleration as it comes to rest. (For comparison, humans lose consciousness with an acceleration of about 7g .)
Assuming the torso is in free fall for a distance of 1.21 m as it falls to the ground, how much time is required for the torso to come to rest once it contacts the ground?
Initial velocity, v0=0 m/s
acceleration due to gravity, g = -9.8 m/s/s
final velocity (end of free fall), v
distance fallen, S = 1.21 m
what is v?
The moment rex is in contact with the ground, decelleration starts.
Using the upward acceleration from part a., we can apply the formula
v=velocity at impact, calculated above.
A=upward acceleration calculated from part a.
t can be isolated and calculated.