Posted by **Mia** on Wednesday, September 23, 2009 at 8:56pm.

Paleontologists estimate that if a Tyrannosaurus rex were to trip and fall, it would have experienced a force of approximately 260,000 N acting on its torso when it hit the ground.

Question 1

Assuming the torso has a mass of 3800 kg , find the magnitude of the torso's upward acceleration as it comes to rest. (For comparison, humans lose consciousness with an acceleration of about 7g .)

Question 2

Assuming the torso is in free fall for a distance of 1.21 m as it falls to the ground, how much time is required for the torso to come to rest once it contacts the ground?

- Physics question -
**MathMate**, Wednesday, September 23, 2009 at 11:10pm
a.

Use F=mA

F=260,000 N

m=3800kg

acceleration A=?

b. v²-v0²=2aS

Initial velocity, v0=0 m/s

acceleration due to gravity, g = -9.8 m/s/s

final velocity (end of free fall), v

distance fallen, S = 1.21 m

what is v?

The moment rex is in contact with the ground, decelleration starts.

Using the upward acceleration from part a., we can apply the formula

v2=v+At

v2=final velocity=0

v=velocity at impact, calculated above.

A=upward acceleration calculated from part a.

t can be isolated and calculated.

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