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March 27, 2017

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Paleontologists estimate that if a Tyrannosaurus rex were to trip and fall, it would have experienced a force of approximately 260,000 N acting on its torso when it hit the ground.

Question 1
Assuming the torso has a mass of 3800 kg , find the magnitude of the torso's upward acceleration as it comes to rest. (For comparison, humans lose consciousness with an acceleration of about 7g .)

Question 2
Assuming the torso is in free fall for a distance of 1.21 m as it falls to the ground, how much time is required for the torso to come to rest once it contacts the ground?

  • Physics question - ,

    a.
    Use F=mA
    F=260,000 N
    m=3800kg
    acceleration A=?

    b. v²-v0²=2aS
    Initial velocity, v0=0 m/s
    acceleration due to gravity, g = -9.8 m/s/s
    final velocity (end of free fall), v
    distance fallen, S = 1.21 m
    what is v?

    The moment rex is in contact with the ground, decelleration starts.
    Using the upward acceleration from part a., we can apply the formula
    v2=v+At
    v2=final velocity=0
    v=velocity at impact, calculated above.
    A=upward acceleration calculated from part a.
    t can be isolated and calculated.

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