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March 5, 2015

March 5, 2015

Posted by **Precilla** on Wednesday, September 23, 2009 at 8:30pm.

Determine the distance x in meters that the rope must sag if it is to be within its recommended safety range and Christian's mass is 74.0kg.

If the Tyrolean traverse is incorrectly set up so that the rope sags by only one-fourth the distance found in part A, determine the tension force (in Newtons) in the rope.

Will the rope break?

repost that for me please

- Physics -
**Precilla**, Wednesday, September 23, 2009 at 8:30pmHow do I do it exactly....

- Physics -
**john**, Thursday, March 25, 2010 at 7:01pm7.6

- Physics -
**Cris**, Monday, February 2, 2015 at 2:59amFor anyone who is looking to solve this in the future:

First figure out the angle

F= 2Tsin(theta)-mg

where, F is total force, and here it must be zero to be at equilibrium

T=tension of rope (2.7kN)

mg=mass*grav= 9.8*74

then use Tan(theta) = Opposite/ Adjacent to figure out the length (Opp)

the angle should be under 10-ish, adjacent is 25/2. So your final answer is Opposite side= should be under 2 meters. Mine was 1.7M with slightly different values

Then for the second part, you divide the length (<2meters) by four. then find the new angle where one leg is 12.5 and the other is (length/4) =. you plug that angle into

0=2Tsin(theta)-mg and solve for T :)

My answer was around 10238 N

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