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January 28, 2015

January 28, 2015

Posted by **abby a.** on Wednesday, September 23, 2009 at 8:09pm.

lim x-> 0 (32-32cosx)/64

- math -
**Reiny**, Wednesday, September 23, 2009 at 8:19pmStep 1 in any limit question is to actually substitute the approach value into the expression.

If you get a real number as an answer, that is it, you are done

so lim (32-32cosx)/64 as x --> 0

= (32-32(1))/64 = 0

end of question.

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