math
posted by abby a. on .
I donot understand how to do this practice question for a test I have tomorrow. can someone please show me step by step? (> is an arrow)
lim x> 0 (3232cosx)/64

Step 1 in any limit question is to actually substitute the approach value into the expression.
If you get a real number as an answer, that is it, you are done
so lim (3232cosx)/64 as x > 0
= (3232(1))/64 = 0
end of question.