Posted by Ashley on Wednesday, September 23, 2009 at 3:33pm.
The weight registered on the scale will show zero if the elevator is in free-fall.
If the elevator is accelerating downwards, the scale will register less than the actual weight.
Let m=mass of the person,
a=acceleration downwards,
g=acceleration due to gravity, 9.8 m/s/s
then
net force on the scale
=m(a-g)=0.74mg
a-g = 0.74g
a=(1-0.74)g=0.26g m/s/s
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