hi, I have redone this question. Is this right.
How many grams of NO2 will be produced when 5.00 moles of NO react?
5 moles of NO2 produces 5 moles of NO (1:1ratio) mass(g) = 5 moles * 46g/mol
= 230g
Write the equation first:
NO + O2 ----> NO2
Balance the equation:
2NO + O2 -----> 2NO2
5mols of NO will form 5mols of NO2
so, they ask how many grams, that would be 230g, correct! :)
right.
Hi! It looks like you're asking about the reaction between NO and NO2. The question asks how many grams of NO2 will be produced when 5.00 moles of NO react.
To solve this, you correctly identified the stoichiometry of the reaction, which is a 1:1 ratio between NO and NO2. This means that for every mole of NO that reacts, one mole of NO2 is produced.
To find the mass of NO2 produced, you can use the molar mass of NO2, which is 46 g/mol. Since the ratio is 1:1, the mass of NO2 produced will be the same as the mass of NO consumed.
Therefore, to find the grams of NO2 produced, you can multiply the number of moles of NO (5.00 moles) by the molar mass of NO2 (46 g/mol):
5.00 moles NO * 46 g/mol = 230 g NO2
So, the correct answer is 230 grams of NO2 will be produced when 5.00 moles of NO react.