Posted by **Jordan** on Tuesday, September 22, 2009 at 11:04pm.

A car starts from rest on a curve with a radius of 120m and accelerates at 1.0m/s^2. Through what angle will the car have traveled when the magnitude of its total acceleration is 2.0 m/s^2?

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**drwls**, Wednesday, September 23, 2009 at 1:57am
Total acceleration consists of two perpendicular components. The centripetal acceleration is V^2/R. The tangential acceration is given to be 1.0 m/s^2.

When the total acceleration is 2.0, the centripetal acceleration is sqrt(2^2 - 1^2) = sqrt3 = 1.732 m/s^2

Solve V^2/R = 1.732 for V, and then use that V to tell you how long and through what angle it has traveled.

V = sqrt(120*1.732) = 14.4 m/s

It takes 14.4 s to attain this speed at the acceleration rate of 1.0 m/s^2

Now compute the angle it has moved through after 14.4 s. I will leave that step up to you.

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**Amar**, Wednesday, October 3, 2012 at 6:52pm
i still havent solved

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**Amar**, Wednesday, October 3, 2012 at 6:52pm
how would u solve this

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**Yuki**, Friday, October 5, 2012 at 9:06pm
A car starts from rest on a curve with a radius of 110 m and accelerates at 1.2 m/s^2 .

1) Through what angle will the car have traveled when the magnitude of its total acceleration is 2.1 m/s^2 ?

Please show steps. thank you

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