can anyone show me how to work this problem out thanks in advance

The Census Bureau provides data on the number of young adults, ages 18โ€“24, who are living in their parents' home (the data include single young adults who are living in college dormitories because it is assumed these young adults will return to their parents' home when school is not in session).

Let the variables M and F represent the following events.

1. M = the event a male young adult is living in his parents' home
F = the event a female young adult is living in her parents' home

If we randomly select a male young adult and a female young adult, the Census Bureau data enable us to conclude P(M) = .56 and P(F) = .42 (The World Almanac, 2006). The probability that both are living in their parents' home is .24.

What is the probability both young adults selected are living on their own (neither is living in their parents' home) (to 2 decimals)?

any can help me please?

idk i need help with this question right now!!

To find the probability that both young adults selected are living on their own (neither is living in their parents' home), we need to calculate the complement of the event that both are living in their parents' home.

Let A be the event that both young adults are living in their parents' home. We are given that P(A) = 0.24.

The complement of A, denoted as A', represents the event that both young adults are living on their own. The complement of an event A is equal to 1 minus the probability of the event A.

So, to find P(A'), we can use the formula: P(A') = 1 - P(A)

Substituting the given value, we have: P(A') = 1 - 0.24

Calculating this, we get: P(A') = 0.76

Therefore, the probability that both young adults selected are living on their own (neither is living in their parents' home) is 0.76 (to 2 decimals).