Posted by **aaron** on Tuesday, September 22, 2009 at 10:46pm.

can anyone show me how to work this problem out thanks in advance

The Census Bureau provides data on the number of young adults, ages 18–24, who are living in their parents' home (the data include single young adults who are living in college dormitories because it is assumed these young adults will return to their parents' home when school is not in session).

Let the variables M and F represent the following events.

1. M = the event a male young adult is living in his parents' home

F = the event a female young adult is living in her parents' home

If we randomly select a male young adult and a female young adult, the Census Bureau data enable us to conclude P(M) = .56 and P(F) = .42 (The World Almanac, 2006). The probability that both are living in their parents' home is .24.

What is the probability both young adults selected are living on their own (neither is living in their parents' home) (to 2 decimals)?

## Answer This Question

## Related Questions

- math statistics/probability - can anyone show me how to work this problem out ...
- statistics - According to the Census Bureau's 2002 American Community Survey, ...
- statistics - According to the Census Bureau's 2002 American Community Survey, ...
- Math - A census-taker rings Mr. Manning's bell and asks how many children he has...
- Math - A census taker came back to a house where a man lived with his three ...
- Grade 8 Math PLZ PPL help its hard - A census-taker rings Mr. Manning's bell ...
- Health (Ms. Sue) - 1. Describe three ways that teens can take on more ...
- Math - The census taker says, "I need to know the ages of your children." The ...
- Intermediate Algebra - Hello I need a little help with my homework. I started ...
- Math - According to the U. S. Census Bureau, the total 2008 U.S. population was ...

More Related Questions