Flamingos have 2 legs lions have 4 legs there are 72 animals totaling 200 legs how many are flamingos
L = lions
F = flamingos
=================
Total = 72 therefore,
L + F = 72
Legs total 200 therefore,
4L + 2F = 200
Solve the two equation.
I get L = 28
To determine the number of flamingos in the group, we'll need to use algebra to solve the problem. Let's break down the information we have:
1. Flamingos have 2 legs each.
2. Lions have 4 legs each.
3. The total number of animals is 72.
4. The total number of legs is 200.
Let's represent the number of flamingos as "F" and the number of lions as "L." Based on the given information, we can set up two equations:
1. The total number of animals: F + L = 72
2. The total number of legs: 2F + 4L = 200
Now, we can solve this system of equations to find the values of F and L.
First, rearrange the first equation to solve for F:
F = 72 - L
Now substitute this value of F into the second equation:
2(72 - L) + 4L = 200
Simplify the equation:
144 - 2L + 4L = 200
2L = 200 - 144
2L = 56
L = 56 / 2
L = 28
So, there are 28 lions in the group.
Now, substitute the value of L back into the first equation to find the number of flamingos:
F + 28 = 72
F = 72 - 28
F = 44
Therefore, there are 44 flamingos in the group.