Posted by **Anonymous** on Tuesday, September 22, 2009 at 8:45pm.

The max. weight M that can be supported by a beam is jointly proportional to its width w and the square of its height h, and inversely proportional to its length L.

a) write an equation that expresses the proportionality.

b) determine the constant of proportionality if a beam is 4 in. wide, 6 in. high, and 12 ft long can support a weight of 4800 lb.

c) if a 10-ft beam, made of the same material is 3 in. wide and 10 in.high, what is the max. weight it can support?

- Math: Calculus -
**Reiny**, Tuesday, September 22, 2009 at 8:50pm
M = k(w)h^2/l

b)4800 = k(4)(36)/12

solve for k

c) now that you have the full equation, just sub in the values given to find M

- Math: Calculus -
**azeb**, Friday, June 22, 2012 at 8:15pm
a)M=k(w)h^2/l

b)4800=k(4)(6)^2/144

k=4800 first change the unit of the length from feet to inch and use the expression that i used above.Unit conversion between in and feet is 1ft=30.48cm and 1in=2.54cm

c)since u have the equation all u have to do is plug in the values to the equation

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