Posted by sundus on Tuesday, September 22, 2009 at 8:44pm.
We don't get to see the figure 3-39, but I assume that the angle 37° is an angle of elevation, that is, it is shot upwards.
Resolve the velocity into the horizontal (cos37°) and vertical (sin37°) components.
Without air resistance, the horizontal component will not vary, i.e. it is a constant velocity.
The vertical component can be treated like a projectile shot vertically upwards, and the usual kinematics formulae will apply.
v0=115sin37° m/s
a=-9.8 m/s/s
S= -125 m when it hits the ground
t=time in seconds
2aS = v0t+(1/2)at²
Solve for the quadratic to get t.
Can you take it from here?
stuff
y 2aS = v0t+(1/2)at² ?????
I need help with the same problem! :(
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