Posted by Amelie on Tuesday, September 22, 2009 at 4:37pm.
I'm trying to solve the problem: 6ybracket 3y(y+7)bracket. I got an answer of 4y7 multiple times. However, my book said the answer is 4y+7. I do not see how the 7 can be positive. I distributed the negative, so therefore, the seven should be negative. Or are parenthesis within brackets exempt from negative signs outside the brackets? Thanks for your help?

Algebra  annaiiz, Tuesday, September 22, 2009 at 5:18pm
you do whats in the brackets first
like 3y(y+7)
you take out the parenthesis and then you subtract 3yy+7=2y+7
now you have 6y[2y+7]
now you take the brackets away
6y2y+7=4y+7