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Posted by on Tuesday, September 22, 2009 at 4:37pm.

I'm trying to solve the problem: 6y-bracket 3y-(y+7)bracket. I got an answer of 4y-7 multiple times. However, my book said the answer is 4y+7. I do not see how the 7 can be positive. I distributed the negative, so therefore, the seven should be negative. Or are parenthesis within brackets exempt from negative signs outside the brackets? Thanks for your help?

  • Algebra - , Tuesday, September 22, 2009 at 5:18pm

    you do whats in the brackets first
    like 3y-(y+7)
    you take out the parenthesis and then you subtract 3y-y+7=2y+7
    now you have 6y-[2y+7]
    now you take the brackets away
    6y-2y+7=4y+7

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