Thursday

December 18, 2014

December 18, 2014

Posted by **Need Help** on Tuesday, September 22, 2009 at 3:24pm.

find the linear function that fits the data

use the function (a) to predict the record in 2003 and in 2006

find the year when the record will be 43.84 sec.

R(t)=?

what is the predicted record for 2003? sec

what is the predicted record for 2006? sec

In what year will the predicted record be 43.84 seconds?

- Algebra 1 -
**DrBob222**, Tuesday, September 22, 2009 at 4:45pmCheck my thinking on this.

1920 to 1980 = 60 years.

In 60 years the record decreased by 45.8-44.6 seconds = 1.2 seconds or 1.2/60 = 0.02 sec/year.

Therefore, R(t) = 45.8-years83((0.02).

For 2003, that is 2003-1920 = 83 years.

R(2003) = 45.8 - 83(0.02)= ??

2006 is done similarly.

For the last part,

43.84 = 45.8-years(0.02) and solve for years.

Again, check my thinking.

**Answer this Question**

**Related Questions**

algebra - ok i dont get this one in 1920 the record for a certain race was 45.9 ...

algebra - In 1920 the record for a certain race was 45.4 sec. in 1950, it was 41...

Math - In 1920, the record for a certain race was 46.6 sec. In 1980, it was 45.4...

math - in 1920 the record for a certain race was 46.4 sec. In 1960 it was 45.6 ...

Math - how do I solve this problem. In 1920 the record for a certain race was ...

math - In 1920, the record for a certain race was 45.5 sec. In 1970, It was 44.5...

Math - In 1920, the record for a certain race was 46.6 sec. In 1980, it was 45.4...

math (am i correct) - in 1920 the record for a certain race was 46.9 sec. In ...

Algebra 1 - In 1920 the record for a certain race was 45.1 sec. In 1960, it was ...

math - in 1920 the record for a certain race was 46.9 sec. In 1990 it was 45.5 ...