How many grams of NO2 will be produced when 5.00 moles of NO react?

I have 5 moles of NO2 produces 5 moles of NO (1:1ratio)
mass (g)=5 moles times 16.02g/mol=80.1g

Hmmm...

Can you recheck the molar mass (in grams) for NO2?

5 moles of NO2 produces 5 moles of NO (1:1ratio)

mass(g) = 5 moles * 46.01g/mol
= 230g

Correct!

To find the number of grams of NO2 produced when 5.00 moles of NO react, you can use the stoichiometry of the reaction. From the balanced equation provided, it states that 5 moles of NO2 are produced for every 1 mole of NO reacted, with a 1:1 ratio.

To calculate the mass in grams, you can use the molar mass of NO2, which is approximately 46.01 grams/mole. Multiply the number of moles of NO reacted (5.00 moles) by the molar mass of NO2 (46.01 grams/mole). This will give you the mass of NO2 produced.

So,

mass (g) = number of moles * molar mass
mass (g) = 5.00 moles * 46.01 grams/mole
mass (g) = 230.05 grams

Therefore, 5.00 moles of NO will produce 230.05 grams of NO2.