Posted by **Emily** on Tuesday, September 22, 2009 at 12:07am.

"A rectangular pasture is subdivided into two equal pens. Using the barn as one side and 132 m of fencing for the rest, find the value of x that gives the maximum area, and A(x)."

It gives no diagram whatsoever, so I have no idea if all the sides are the same length or not, etc etc... Can someone show me how to work out this problem please? Any help is GREATLY appreciated!! :D

- Precalculus -
**MathMate**, Tuesday, September 22, 2009 at 12:33am
The fence will look like a letter E. The open end of the letter E is the face of the barn.

It does not matter which length x stands for, as long as the total length of the fence is 132 m.

Let x be one of the three equal sides, and the length of the barn fenced in is 132-3x.

Total area

A(x) = x(132-3x)

A'(x) = 132-6x =0

Therefore x=132/6=22 m

The area is x(132-3x)=22(66)=1452 m²

check: A"(x) = -6 <0, therefore maximum.

- Precalculus -
**Emily**, Tuesday, September 22, 2009 at 12:43am
Ohhhh I totally get it now!!! Thanks! :D

- Precalculus :) -
**MathMate**, Tuesday, September 22, 2009 at 6:43am
Glad that it helped! :)

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