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May 6, 2016

Homework Help: Physics

Posted by Willie on Monday, September 21, 2009 at 7:58pm.

A ball is tied to an elastic string of length 8.0 m and swung in a horizontal circle with a velocity of 0.8 m/s. When a metallic object is tied to a rope of length 2.75 m and swung in a horizontal circle, it makes one revolution in 2.9 s. The ratio of the centripetal force in the string to the centripetal force in the rope is 1/3.0. Find the mass of the metallic object attached to the rope, if the centripetal force in the string is 0.20 N.
• Physics - MathMate, Tuesday, September 22, 2009 at 3:57pm

Centripetal force on string, F1
= m1v²/r1
F1=0.2 N

Centripetal force on rope, F2
= m2r2ω²
Since 3F1=F2, therefore F2=0.6N

Equate F2=m2r2ω²
Since all variables are known except m2,
you can readily solve for m2.

• Physics - ngfhg, Sunday, February 12, 2012 at 12:42pm

• Physics - ngfhg, Sunday, February 12, 2012 at 12:43pm

pllllllllllllllllleeeeeaaassssssse, unless im gonna fail my class

• Physics - ngfhg, Sunday, February 12, 2012 at 12:44pm

kidding, but someone answer this freakin question

• Physics - t7d7fluygiy, Monday, November 10, 2014 at 12:07am

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