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A ball is tied to an elastic string of length 8.0 m and swung in a horizontal circle with a velocity of 0.8 m/s. When a metallic object is tied to a rope of length 2.75 m and swung in a horizontal circle, it makes one revolution in 2.9 s. The ratio of the centripetal force in the string to the centripetal force in the rope is 1/3.0. Find the mass of the metallic object attached to the rope, if the centripetal force in the string is 0.20 N.

  • Physics -

    Centripetal force on string, F1
    = m1v²/r1
    F1=0.2 N


    Centripetal force on rope, F2
    = m2r2ω²
    Since 3F1=F2, therefore F2=0.6N

    Equate F2=m2r2ω²
    Since all variables are known except m2,
    you can readily solve for m2.

  • Physics -

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  • Physics -

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  • Physics -

    kidding, but someone answer this freakin question

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