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March 31, 2015

March 31, 2015

Posted by **Willie** on Monday, September 21, 2009 at 7:51pm.

- Physics -
**MathMate**, Tuesday, September 22, 2009 at 4:07pmConsider only the vertical component (5.376 m/s).

Calculate the time it takes to hit the ground below after reaching a maximum height in the air, since the ball is thrown upwards.

If we can ignore air resistance, the horizontal distance is the product of the horizontal component of initial velocity and the time to reach the ground.

- Physics -
**cherryberry**, Thursday, November 20, 2014 at 1:47pmyou screwed

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