Posted by Willie on Monday, September 21, 2009 at 7:51pm.
A hiker throws a ball at an angle of 21.0 degrees above the horizontal from a hill 21.0 m high. The hiker's height is 1.750 m. The magnitudes of the horizontal and vertical components of the velocity are 14.004 m/s and 5.376 m/s, respectively. Find the distance between the base of the hill and the point where the ball hits the ground.(Consider the hiker's height while calculating the answer.)

Physics  MathMate, Tuesday, September 22, 2009 at 4:07pm
Consider only the vertical component (5.376 m/s).
Calculate the time it takes to hit the ground below after reaching a maximum height in the air, since the ball is thrown upwards.
If we can ignore air resistance, the horizontal distance is the product of the horizontal component of initial velocity and the time to reach the ground.

Physics  cherryberry, Thursday, November 20, 2014 at 1:47pm
you screwed
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