can u arrange 24 children in 6 rows comprising 5 show it?
Arrange the children in the form of a regular hexagon, with 5 children on each side. There are six vertices common to the adjacent sides, i.e. the child at the end of each row is also the end of the adjacent row.
The total number of children required = 5*6-6 = 24.
4 in each row
Yes, I can help you arrange 24 children in 6 rows, with each row comprising 5 children.
To solve this problem, we need to figure out how many groups of 5 we can form using 24 children. Since 5 does not divide evenly into 24, we have to round down to the nearest whole number.
24 divided by 5 equals 4 remainder 4. This means we can form 4 complete groups of 5 children, with 4 children remaining.
To arrange the children, we can start by placing 5 children in each of the 4 rows. That would give us a total of 20 children arranged in 4 rows.
To accommodate the remaining 4 children, we need to distribute one child to each of the 4 rows. Each of the 4 rows now has 6 children in it.
Finally, we can create a new row and place the remaining 4 children in it. Now we have a total of 24 children arranged in 6 rows, with each row comprising 5 children.
Here is a visual representation of the arrangement:
Row 1: 5 children
Row 2: 5 children
Row 3: 5 children
Row 4: 5 children
Row 5: 6 children
Row 6: 4 children
I hope this helps! Let me know if you have any further questions.