Posted by **louden** on Sunday, September 20, 2009 at 10:43pm.

While exploring a cave, a spelunker starts at the entrance and moves the following distances: 75.0 m north, 260 m east, 195 m at an angle 30.0° north of east, and 150 m south. Find the resultant displacement from the cave entrance.

- physics -
**MathMate**, Monday, September 21, 2009 at 12:19am
Let x=east, y=north

and 0° towards the +x-axis (due East)

and 90° = due north.

Separate each displacement into the x- and y-components and add.

distance angle x y

75m N=90° 75cos(90°) 75sin(90°)

260m E=0° 260cos(0) 260sin(0)

195m 30°N of E = 30° 195cos(30°) 195sin(30°)

...

Add up algebraically the x- and y-components. The sum will be the x- and y-components of the resultant displacement vector.

- physics -
**MathMate**, Monday, September 21, 2009 at 12:22am
A cave explorer is called a speleologist.

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