solve
x^2 = 2^x
one obvious solution is x = 2
if we graph y = x^2 and y = 2^x we see there is another solution between 0 and -1
Using a procedure called Newton's Method, I found the other root to be appr. -.767
x^2 = 2^x
if we graph y = x^2 and y = 2^x we see there is another solution between 0 and -1
Using a procedure called Newton's Method, I found the other root to be appr. -.767