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March 5, 2015

March 5, 2015

Posted by **Joanne** on Sunday, September 20, 2009 at 7:09pm.

- Math -
**Ms. Sue**, Sunday, September 20, 2009 at 7:13pmYour

__School Subject__is**Math**, not "college."

- Math -
**Reiny**, Sunday, September 20, 2009 at 7:49pmsince you labeled it "college" I will assume you know Calculus.

N(x)=0.4x^2+8x+11

N'(x) = .8x + 8

= 0 for a max/min of N

.8x + 8 = 0

x will be a negative, so your problem makes no sense.

your function is an upwards parabola so it has a minimum, not a maximum.

perhaps you have a typo and the first term is -.8x^2

then the above result becomes

-.8x + 8 = 0

x = 10

and N(10) = -.8(100) + 80 + 11

= 11

11 tickets sold ????

There are more people singing Hallelujah.

- Math -
**jim**, Sunday, September 20, 2009 at 7:49pmApart from the subject, that equation isn't going to peak for x > 0. I think you may have an error in the question.

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