Math
posted by John Smith .
Together these two turkeys weigh twenty pounds," said the butcher. The little fellow sells for two cents a pound more the big one." Mrs. Smith bought the little one for 82 cents and Mrs. Brown paid $2.96 cents for the big turkey. How much did each turkey weigh?
I need the work also

Let the little fellow weigh x lbs
then the big fellow weighs 20x lbs
let the cost of the big fellow be c cents per pound
then the cost of the little fellow is c+2 cents
x(c+2) = 82
cx + 2x = 82 #1
c(20x) = 296
20c  cx = 296 #2
add #1 and #2
2x + 20c = 378
x + 10c = 189
x = 18910c #3
I will let you finish it,
sub #3 into #1 to find c
then back into #3 to find x
cheap turkeys, must be old question 
I don't get the last part:
I will let you finish it,
sub #3 into #1 to find c
then back into #3 to find x
Please help me through this!
Is it
(cx+2x)  (18910c)? 
x = 18910c
then in #1
c(18910c) + 2(18910c) = 82
expanding this and lining it up as a quadratic
10c^2  169c  296 = 0
I used the quadratic formula to get
c = 18.5
now back into #3
x = 189  10(18.5)
x = 4
so the little fellow weighed 4 lbs
and the big one weighed 16 lbs
the big one cost 18.5 cents a pound
the little one cost 20.5 cents a pound
check: 20.5x4 = 82
16x18.5 = 296