Posted by **John Smith** on Sunday, September 20, 2009 at 5:48pm.

Together these two turkeys weigh twenty pounds," said the butcher. The little fellow sells for two cents a pound more the big one." Mrs. Smith bought the little one for 82 cents and Mrs. Brown paid $2.96 cents for the big turkey. How much did each turkey weigh?

I need the work also

- Math -
**Reiny**, Sunday, September 20, 2009 at 6:41pm
Let the little fellow weigh x lbs

then the big fellow weighs 20-x lbs

let the cost of the big fellow be c cents per pound

then the cost of the little fellow is c+2 cents

x(c+2) = 82

cx + 2x = 82 #1

c(20-x) = 296

20c - cx = 296 #2

add #1 and #2

2x + 20c = 378

x + 10c = 189

x = 189-10c #3

I will let you finish it,

sub #3 into #1 to find c

then back into #3 to find x

cheap turkeys, must be old question

- Math -
**John Smith**, Sunday, September 20, 2009 at 7:42pm
I don't get the last part:

I will let you finish it,

sub #3 into #1 to find c

then back into #3 to find x

Please help me through this!

Is it

(cx+2x) - (189-10c)?

- Math -
**Reiny**, Sunday, September 20, 2009 at 8:16pm
x = 189-10c

then in #1

c(189-10c) + 2(189-10c) = 82

expanding this and lining it up as a quadratic

10c^2 - 169c - 296 = 0

I used the quadratic formula to get

c = 18.5

now back into #3

x = 189 - 10(18.5)

x = 4

so the little fellow weighed 4 lbs

and the big one weighed 16 lbs

the big one cost 18.5 cents a pound

the little one cost 20.5 cents a pound

check: 20.5x4 = 82

16x18.5 = 296

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